- #1

zanyzoya

Gold Member

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## Homework Statement

An ice cube of mass 0.01.kg at a temperature of 0 degrees Celsius is dropped into a cup containing 0.10kg of water at a temperature of 15 degrees Celsius. What is the max estimated change in temperature of the contents of the cup?

SHC of water = 4200J per kg per kelvin

latent heat of fusion of ice = 340000 J per kg

## Homework Equations

and attempt at a solution[/B]heat lost by water = heat gained by ice

m

_{water}C ΔT

_{water}= m

_{ice}C ΔT

_{ice}+ mΔL

0.1 x 4200 x ΔT

_{water}= 0.01 x 4200 ΔT

_{ice}+ 0.01 x 340000

420(T

_{final}-15) = 42 (T

_{final}-0) + 3400

420T - 6300 = 42T + 3400

T= 25 degrees

so change in temperature = 15-25 = -10 degrees celcius

This is wrong as the actual answer is 8.7 K